Answer to Question #252819 in Mechanics | Relativity for Danny

Question #252819

a ball is thrown vertically upwards with a speed of 40ms^-1. Find the height of the ball when it is moving at 10ms^-1


1
Expert's answer
2021-10-18T10:57:52-0400

The height is

"H=\\frac{v^2-u^2}{2g}=76.5\\text{ m}."



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