Question #25171

A wave has a wave speed of 243 m/s and a wavelength of 3.27 cm. Calculate (a) the frequency and (b) the period of the wave.

Expert's answer

v=243msλ=3.27cm=0.0327mv = 243 \frac{m}{s} \quad \lambda = 3.27 \text{cm} = 0.0327 \text{m}


We know, that period can be found as T=λv=0.0327m243m/s=134.5106s=134.5microsecT = \frac{\lambda}{v} = \frac{0.0327\text{m}}{243\text{m/s}} = 134.5 \cdot 10^{-6}\text{s} = 134.5\text{microsec}

The frequency is inverse to period: f=1T=1134.5106=7435Hz=7.435kHzf = \frac{1}{T} = \frac{1}{134.5} \cdot 10^{6} = 7435\text{Hz} = 7.435\text{kHz}

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