We know, that period can be found as T=λv=0.0327m243m/s=134.5⋅10−6s=134.5microsecT = \frac{\lambda}{v} = \frac{0.0327\text{m}}{243\text{m/s}} = 134.5 \cdot 10^{-6}\text{s} = 134.5\text{microsec}T=vλ=243m/s0.0327m=134.5⋅10−6s=134.5microsec
The frequency is inverse to period: f=1T=1134.5⋅106=7435Hz=7.435kHzf = \frac{1}{T} = \frac{1}{134.5} \cdot 10^{6} = 7435\text{Hz} = 7.435\text{kHz}f=T1=134.51⋅106=7435Hz=7.435kHz
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