Question#25143
an apple drops from a tree and hits the ground in one second. what is it's speed upon striking the ground? what is the average speed during the one second? how high above ground was it when it's first dropped?
Solution:
Let:
t=1 sec
v=?, vaverage=?, H=?
v=gt, were g is the acceleration of gravity
H=21gt2vaverage=tH=21gtv=9.8∗1=9.8m/secH=219.8∗1=4.9mvaverage=14.9=4.9m/sec
Answer: the speed is 9.8 m/sec, the average speed is 4.9 m/sec, the high above the ground is 4.9 m.