Answer to Question #251335 in Mechanics | Relativity for Fat

Question

A particle is displayed 60 cm to the north and then is given a second displacement of 90 cm to the east. what is the average velocity of the particle if it covers the displacement within 2.15 

Answer 1

First, find the displacement:

$$d=\sqrt{0.6^2+0.9^2}=1.08\text{ m}.$$

The average velocity is the displacement over time:

$$v=\frac{d}{t}=\frac{1.08}{2.15}=0.5\text{ m/s}.$$