How much work was required to bring the 1000-kg roller coaster from point P to rest at point Q at the top of the 50-m peak?
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Expert's answer
2013-02-27T04:48:16-0500
The work is equal to the change of potential energy V ofthe coaster.
The value of V at the height h is equal to V(h) = m*g*h, where g=9.8 m/s^2. Thus, A = V(h) - V(0) = m * g * h - 0 = = m * g * h = = 1000 * 9.8 * 50 = 490000 J.
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