Question

A simple machine raises a load of 75kg through a distance of 0.6m. The effort applied to

the machine is 250N and moves through a distance of 18m. Taking g as 9.8m/s²,

determine, The mechanical advantage, The velocity ratio, & The efficiency of the machine.

Answer 1

$M.A=L/E=75\times 9.8/250=2.94$

V.R= distance moved by effort$/$ distance moved by load=$18m/0.6m=30$

$efficiency=M.A/V.R \times 100\%=2.94/30\times 100\%=9.8\%$