The energy can be found from the relation E=hν=hc/λ, where λ is the wavelength of the quantum. After substitution, we find for λ = 400 nm the energy as
E1=λhc=400×10−9m(6.626×10−34Js)(3×108m/s)E1=4.9695×10−19J
Then for the second quantum, we calculate the energy for λ = 2.7 μm:
E2=λhc=2.7×10−6m(6.626×10−34Js)(3×108m/s)E2=7.3622×10−20J
The relation between the energies is
E2/E1=4.9695×10−19J7.3622×10−20J=0.1481
Reference:
- Sears, F. W., & Zemansky, M. W. (1973). University physics.
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