A body of mass 700g falls from a height of 10m.Find the momentum of the
body.
s=v2/(2g)→v=2gs=2⋅9.8⋅10=14 (m/s)s=v^2/(2g)\to v=\sqrt{2gs}=\sqrt{2\cdot 9.8\cdot 10}=14\ (m/s)s=v2/(2g)→v=2gs=2⋅9.8⋅10=14 (m/s)
p=mv=0.7⋅14=9.8 (kg⋅m/s)p=mv=0.7\cdot14=9.8\ (kg\cdot m/s)p=mv=0.7⋅14=9.8 (kg⋅m/s) . Answer
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