A body of mass 700g falls from a height of 10m.Find the momentum of the
body.
"s=v^2\/(2g)\\to v=\\sqrt{2gs}=\\sqrt{2\\cdot 9.8\\cdot 10}=14\\ (m\/s)"
"p=mv=0.7\\cdot14=9.8\\ (kg\\cdot m\/s)" . Answer
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