Question

bryle pushes a 50.0 kg sack of rice across a level floor by a horizontal force of 35.0N against a frictional force of 12.0 N. He succeeded in moving the sack to a distance of 5.0m. How much work is done by (a) bryle (b) friction and (c) force of gravity?

Answer 1

(a) $W=Fs=35\cdot5=175\ (J)$

(b) $W=Fs=15\cdot5=75\ (J)$

(c) $W=Fs=50\cdot9.8\cdot0=0\ (J)$