Question

Fx=0=T2X-T1X=T2cos(10degrees)-T1sin(10degrees)

Answer 1

$$\mathrm{Fx} = 0 = \mathrm{T2X} - \mathrm{T1X} = \mathrm{T2cos}(10\text{degrees}) - \mathrm{T1\sin}(10\text{degrees})$$

Solution

$$F_x = 0 = T_{2X} - T_{1X} = T_2 \cos(10{}^\circ) - T_1 \sin(10{}^\circ)$$

We know that

$$\cos(10{}^\circ) \cong 0.98, \sin(10{}^\circ) \cong 0.17.$$

Then we have

$$0.98T_2 - 0.17T_1 = 0 \rightarrow \frac{T_1}{T_2} = 5.67$$

Answer: $\frac{T_1}{T_2} = 5.67$.