Answer to Question #246702 in Mechanics | Relativity for ksdfsd

Question

Metabolizing a candy bar releases about 10

6

106 joules of energy. Assume the candy bar's mass is 0.12 kg

kgand use the formula kinetic energy =1

2

mv

2

=12mv2, where m

m is the object's mass and v

v is its velocity. How fast must the candy bar travel to have the same 10

6

106 joules in the form of kinetic energy?

Answer 1

Rearranging the equation $E=\frac{1}{2}mv^2$ to solve for $v$, we get:

$v=\sqrt{\frac{2E}{m}}=\sqrt{\frac{2\times10^6J}{0.12kg}}=4.1\times10^3\space{m/s}$

Answer: $4.1\times10^3\space{m/s}$