Question

In a single pendulum a bulb was tied to a thread of length 27cm what is the angular velocity and period of oscillation

Answer 1

Angular Velocity=$\omega$²=$g/L$ =$9.8/0.27$ =$36.296$

$\omega$ =$√36.296=6.025$

$T=2\pi$ $√L/g=2×22/7×√0.27/9.8=0.176seconds$