A cheetah can run at a maximum speed 105 km/h and a gazelle can run at a maximum speed of 76 km/h. If both animals are running at full speed, with the gazelle 79.2 m ahead, how long before the cheetah catches its prey? Answer in units of s.
x=x0+vxtx = x_0+v_xtx=x0+vxt
For cheetah: x0=0;vc=105kmh\text{For cheetah: }\newline x_0 = 0;v_c= 105\frac{km}{h}For cheetah: x0=0;vc=105hkm
x=105t(1)x= 105t(1)x=105t(1)
For gazelle: x0=79.2m=79.2∗10−3km;vc=76kmhx=79.2∗10−3+76t(2)\text{For gazelle: }\newline x_0 = 79.2m =79.2*10^{-3}km;v_c= 76\frac{km}{h}\newline x= 79.2*10^{-3}+ 76t(2)For gazelle: x0=79.2m=79.2∗10−3km;vc=76hkmx=79.2∗10−3+76t(2)
Equate (1) and (2):79.2∗10−3+76t=105t\text{Equate (1) and (2):}\newline 79.2*10^{-3}+76t= 105tEquate (1) and (2):79.2∗10−3+76t=105t
t=79.2∗10−329h=79.2∗10−3∗360029s=9.83st = \frac{79.2*10^{-3}}{29}h=\frac{79.2*10^{-3}*3600}{29}s=9.83st=2979.2∗10−3h=2979.2∗10−3∗3600s=9.83s
Answer: 9.83s\text{Answer: }9.83sAnswer: 9.83s
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