Answer to Question #243914 in Mechanics | Relativity for Ghadeer Almarzooq

Question

A person standing on a frictionless surface has a mass of 69.5kg including the gun is holding . He fires a 4.2g round at 955m/s.
Find the recoil velocity of the hunter if his fire horizontally.

Answer 1

By the principle of conservation of impulse:

$m_1v_1+m_2v_2=0$

where m₁ is mass of person, m₂ is mass of bullet,

v₁ is recoil velocity of the hunter, v₂ is velocity of bullet.

$v_1=-\frac{m_2v_2}{m_1}=-\frac{4.2\cdot 10^{-3}\cdot 955}{69.5}=-0.06$ m/s