Question #243465

A vector A  has components Ax = 12.0 m and Ay= 5.00 m. What is the angle that vector A  makes with the x-axis?


1
Expert's answer
2021-09-28T17:11:21-0400

tanθ=Ay/Ax=5/12=0.4167tan \theta= Ay/Ax=5/12=0.4167

θ=tan10.4167=22.62o\theta=tan^{-1}0.4167=22.62^o


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