in a hydraulic pressure, a force of 20N is applied to a piston of area 0.2m^2, if the area of the other piston is 2m^2. calculate the force excerted on it.
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Expert's answer
2021-09-27T09:01:47-0400
Using Pascal's law for F1= 20 N, A1 = 0.2 m2 and A2 = 2 m2:
P1=P2A1F1=A2F2⟹F2=F1A1A2
We substitute and we can find the force exerted on the piston 2 or F2:
F2=(20N)(0.2m22m2)=200N
In conclusion, the force exerted on the piston (of area A2 = 2 m2) is 200 N.
Reference:
Sears, F. W., & Zemansky, M. W. (1973). University physics.
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