Question #24249

what is the pressure that an object exerts on the floor that has a weight of 500N and and area of .001m squared?

Expert's answer

QUESTION:

What is the pressure that an object exerts on the floor that has a weight of 500N and area of .001m squared?

SOLUTION:

Pressure is the ratio of force F to the area S over which that force is distributed.


p=Fsp = \frac{F}{s}


Here F=500 NF = 500\ \mathrm{N} and S=0.001 m2S = 0.001\ \mathrm{m}^2. Hence


p=5000.001=0.5 MPap = \frac{500}{0.001} = 0.5\ \mathrm{MPa}

ANSWER:

p=5000.001=0.5 MPap = \frac{500}{0.001} = 0.5\ \mathrm{MPa}

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