Given: G = 6.67259 × 10−11 Nm2/kg2 .
A 1340 kg geosynchronous satellite or-
bits a planet similar to Earth at a radius
1.97 × 105 km from the planet’s center. Its
angular speed at this radius is the same as the
rotational speed of the Earth, and so they ap-
pear stationary in the sky. That is, the period
of the satellite is 24 h .
What is the force acting on this satellite?
Answer in units of N
012 (part 2 of 2) 10.0 points
What is the mass of this planet?
Answer in units of kg
1
Expert's answer
2013-02-19T07:54:22-0500
1) The forceacting on this satellite: F = G*m*M/R^2 G - gravitational constant m - mass of thу satellite M - mass of the planet R - radius of the orbit M = (2Pi/T)^2/G*R^3 (from 2nd part) F = G*m*(2Pi/T)^2/G*R^3/R^2 = m*(2Pi/T)^2*R = 1396.06 H 2) Newton's second laws of motion: mV^2/R = G*m*M/R^2 V - speed of the satellite. V^2 = G*M/R M = R*V^2/G 2*Pi*R/T = V M = R*(2*Pi*R/T)^2/G = (2Pi/T)^2/G*R^3 = 6.0595*10^26 kg
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
"assignmentexpert.com" is professional group of people in Math subjects! They did assignments in very high level of mathematical modelling in the best quality. Thanks a lot
Comments
Leave a comment