Question #24151

A coordinate system (in meters) is con-
structed on the surface of a pool table, and
three objects are placed on the coordinate sys-
tem as follows: a 1.5 kg object at the origin,
a 2.9 kg object at (0 m,2.4 m), and a 4 kg
object at (3.5 m,0 m).
Find the resultant gravitational force ex-
erted on the object at the origin by the other
two objects. The universal gravitational con-
heath (jh56532) – Circular Motion – suarez – (A2111) 2
stant is 6.672 × 10−11 N · m2/kg2 .
Answer in units of N
014 (part 2 of 2) 10.0 points
At what angle does it act with respect to
the positive x axis? Let counterclockwise be
positive, within the limits of −180 to 180.
Answer in units of

Expert's answer


1) The force between 2 bodies:

F = G*m1*m2/R^2

G - gravitational constant

m1, m2 - masses of bodies

R - distance between them

For body (0, 0) and (0, 2.4)

F1 = G 1.5*2.9/(2.4)^2 = 5.04 × 10^-11 H

For body (0, 0) and (3.5, 0)

F1 = G 1.5*4/(3.5)^2 = 3.27 × 10^-11 H


F1+F1=F12+F22=6×1011H| F 1 + F 1 | = \sqrt {F 1 ^ {2} + F 2 ^ {2}} = 6 \times 1 0 ^ {- 1 1} \mathrm {H}


2) The angle respect the positive xx axis:

tan(α)=5.04×10113.27×1011=1.54\tan (\alpha) = \frac{5.04\times 10^{-11}}{3.27\times 10^{-11}} = 1.54

α=tan11,54=57\alpha = \tan^{-1} 1,54 = 57

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