Question #24027

I am trying to figure out how to solve the following: Calculate the speed of an 8.0 x 10(to the 4th)kg airliner with a kinetic energy of 1.1 x 10(to the 9th) J.

Expert's answer

Calculate the speed of an 8.0×108.0 \times 10 (to the 4th) kg airliner with a kinetic energy of 1.1×101.1 \times 10 (to the 9th) J.

**Solution.**


m=8104kg,Ek=1.1109J;m = 8 \cdot 10^{4} \, kg, \, E_k = 1.1 \cdot 10^{9} \, J;v?v - ?


The kinetic energy of the airliner we calculate by formula:


Ek=mv22;E_k = \frac{m v^2}{2};

EkE_k - the kinetic energy of the airliner;

mm - the mass of the airliner;

vv - the speed of the airliner.


2Ek=mv2;2E_k = m v^2;v2=2Ekm.v^2 = \frac{2E_k}{m}.v=2Ekm.v = \sqrt{\frac{2E_k}{m}}.v=21.11098104=165.83(ms).v = \sqrt{\frac{2 \cdot 1.1 \cdot 10^{9}}{8 \cdot 10^{4}}} = 165.83 \left(\frac{m}{s}\right).


**Answer:** The speed of the airliner is v=165.83msv = 165.83 \, \frac{m}{s}.


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