Answer to Question #239857 in Mechanics | Relativity for Maliha

Question

a.      The helicopter lifts the vehicle of mass 1500 kg at a vertical acceleration of 3.0 m s–2. Show that the tension in the cable is 1.9 ´ 104 N.

 

At a later time, the helicopter is moving forward in level flight at a constant velocity of 50 m s–1. The cable carrying the vehicle now hangs at a steady angle of 15°  to the vertical as shown in the diagram below.

b.     Draw labelled arrows on the diagram to show and name the forces acting on the vehicle.

c.      Calculate the tension in the cable in this case.

d.     Calculate the size of the drag force on the car.

 

Answer 1

Explanations & calculations

a)

• Apply F=ma for the vertical motion of the vehicle.

$\qquad\qquad \begin{aligned} \small \uparrow T-mg&=\small ma\\ \small T&=\small m(g+a)=1500kg\times(9.8+3.0)\\ &=\small 19200N\approx 19000\\ &\approx \small 1.9\times10^4N \end{aligned}$

b)

• Give it a try to find the tension & the drag force by resolving the tension appropriately.
• I hope you are aware of resolving a given force accordingly.
• Give it a try & if you are unable in case, ask me again on this site.