A car moving along a straight level road has an initial velocity of 16ms^-1. It's deceleration is 2ms^-2. How long does it take for the car to stop?
1
Expert's answer
2013-02-05T09:02:44-0500
a = dv/dt a - acceleration ( -a - deceleration ) v - velocity t - time Therefore: v = a*t + v0 v0 - initial velocity In our case: v = 0 = 16 - 2*t ( car stops) t = 16/2 = 8 seconds Answer: 8 seconds.
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
"assignmentexpert.com" is professional group of people in Math subjects! They did assignments in very high level of mathematical modelling in the best quality. Thanks a lot
Comments
Leave a comment