Answer to Question #236399 in Mechanics | Relativity for Jick

Question #236399

A truck is stopped at a stoplight. When the light turns green, it accelerates at 2.5 m/s2. At the same instant, a car passes the truck going 15 m/s. Where and when does the truck catch up with the car?


1
Expert's answer
2021-09-12T18:59:41-0400

Truck

ut=0vt2=2atstu_t=0 \\ v_t^2 = 2a_ts_t

Car

uc=15  m/sS=uctcS=15tcu_c= 15 \;m/s \\ S= u_ct_c \\ S = 15t_c

Time taken by truck = Time taken by car

tt=tcvt=attS=12at2=12(2.5)t215tk=12(2.5)t2302.5=tctc=12  sS=15×12=180  mt_t =t_c \\ v_t = at_t \\ S= \frac{1}{2}at^2 = \frac{1}{2}(2.5)t^2 \\ 15t_k = \frac{1}{2}(2.5)t^2 \\ \frac{30}{2.5} = t_c \\ t_c=12\;s \\ S= 15 \times 12 = 180 \;m

At time 12 sec and distance 180 m both vehicles will meet.


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