Question

A 10 g bullet moving with a velocity of 500 m/s enters a stationary piece of ice mass 10 kg and stops . If the the piece of ice is lying on a frictionless plane then it's velocity will be?

Answer 1

let mass of the bullet $=m_1$

mass of ice $=m_2$

initial momentum of the bullet$=m_1v_1$

initial mass of ice =0

from conservation of momentum,

total initial momentum = total final momentum

$m_1v_1=(m_1+m_2 )v$

$\frac{10}{1000}\times 500=(\frac{10}{1000}+10)v$

$5=10.01v$

$v=0.4995m/s$ (velocity of ice)