Given that
Density of fluid ρ=7×102kg/m3
Inlet hose radius r1=0.024m
Outlet hose radius r2=0.012m
Pressure difference ΔP=1.2×103Pa
A) From equation of continuity
A1v1=A2v2v1=A1A2v2v12=(πr12πr22)2v22=((0.024m)2(0.012m)2)2v22=(0.0325)v22
Applying Bernoulli’s theorem for a hose pipe of the same height
ΔP=21ρ[v22−v12]=21ρ[v22−(0.0625)v22]=21ρv22[1−0.0625]v2=ρ(1−0.0625)2ΔP=(700kg/m3)×(1−0.0625)2×1200Pa=1.9m/s
b) The flow rate is
Q=A2v2=πr22v22=π×(0.012m)2×(1.9123m/s)=8.65×10−4m3/s
Comments