a ship leaves port at 1 pm traveling north at the speed of 30 miles per hour. At 3 pm the ship adjust its course 20 degrees eastward, how far was the ship from the port at 4pm.
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Expert's answer
2013-01-31T09:33:45-0500
The displacement from 1 pm to 3pm D1 = 30 miles/hr * 2 hr = 60 miles to the North
The displacement from 3 pm till 4 pm D2 = 30 miles/hr * 1 hr = 30 miles to the 20 degrees North Eastward
The resulting displacement, by adding two vectors D = sqrt((D1 + D2*cos(20 deg))^2 + (D2*sin(20 deg))^2) D = sqrt((60 + 30*cos(20 deg))^2 + (30*sin(20 deg))^2) = 88.79 miles
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