Answer to Question #231499 in Mechanics | Relativity for Blossom

Question

^{height of waterfall is 500m high. of the water retains 65% of the heat generated at the end of the fall , calculate the change in temperature due to the fall}

Answer 1

Water is at height (h)=500m.

putting mass of water= 1kg

Potential energy =mgh=$1\times 9.81\times 500=\frac{4905J}{litre}$

$65\% of 4905=\frac{3188.25J}{litre}$

Specific heat of water =4180J$/$ kg$/$ k.

So, E=m$\times$ c$\times$ ΔT

3188.25=$1\times 4180\times$ ΔT

ΔT $=0.76^oC$