Answer to Question #231124 in Mechanics | Relativity for Dasun

Question #231124

Horizontal square shaped platform of side 10 m on the ground has initially sides coinciding with x-axis and y-axis as shown. A platform starts moving along x-axis with a velocity 10 m/s. A person standing on the platform starts moving on platform towards diagonally opposite corner as shown, with a velocity 5​√2m/s. A stationary person standing at origin (Not on the platform) throws a ball in air so that the ball hits the person on platform when it is exactly at corner of the platform. Find the velocity of the ball?

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Expert's answer
2021-08-31T08:59:02-0400

v1=10, v=52,v_1=10,~v=5\sqrt 2,

x=10, d=102,x=10,~d=10\sqrt 2,

t=dv=2,t=\frac dv=2,

l=v1t+x=30,l=v_1t+x=30,

y=x=10,y=x=10,

r=l2+y2=1010,r=\sqrt{l^2+y^2}=10\sqrt{10},

u=rt=510 ms.u=\frac rt=5\sqrt{10}~\frac ms.


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