Question #22941

1. You’re riding a unicorn at 25 m/s and come to a uniform stop at a red light 20 m away. What’s your acceleration?

Expert's answer

Task:

1. You're riding a unicorn at 25m/s25 \, \text{m/s} and come to a uniform stop at a red light 20m20 \, \text{m} away. What's your acceleration?

Solution:

Due to Newton's second law:


F=ma\sum F = m aa=Fma = \frac {\sum F}{m}a=v˙a = \dot {v}v=adt=at+v0v = \int a d t = a t + v _ {0}t=(vv0a)t = \left(\frac {v - v _ {0}}{a}\right)v=s˙v = \dot {s}s=vdt=(at+v0)dt=at22+v0t+s0=a(vv0a)22+v0(vv0a)+s0==v22vv0+v022a+vv0v02a+s0=v2v022a+s0\begin{array}{l} s = \int v d t = \int (a t + v _ {0}) d t = \frac {a t ^ {2}}{2} + v _ {0} t + s _ {0} = \frac {a \left(\frac {v - v _ {0}}{a}\right) ^ {2}}{2} + v _ {0} \left(\frac {v - v _ {0}}{a}\right) + s _ {0} = \\ = \frac {v ^ {2} - 2 v v _ {0} + v _ {0} ^ {2}}{2 a} + \frac {v v _ {0} - v _ {0} ^ {2}}{a} + s _ {0} = \frac {v ^ {2} - v _ {0} ^ {2}}{2 a} + s _ {0} \\ \end{array}


Given:


s=20m,s = 2 0 m,v0=25msv _ {0} = 2 5 \frac {m}{s}s0=0ms _ {0} = 0 mv=0msv = 0 \frac {m}{s}20m=(25ms)22a2 0 m = - \frac {\left(2 5 \frac {m}{s}\right) ^ {2}}{2 a}a=(25ms)220m=31.25ms2a = - \frac {\left(2 5 \frac {m}{s}\right) ^ {2}}{2 0 m} = - 3 1. 2 5 \frac {m}{s ^ {2}}


Answer:


a=31.25ms2a = - 3 1. 2 5 \frac {m}{s ^ {2}}

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