A 1590 kg car moving south at 13.5 m/s collides with a 2540 kg car moving north. The
cars stick together and move as a unit after
the collision at a velocity of 5.90 m/s to the
north.
Find the velocity of the 2540 kg car before
the collision.
Answer in units of m/s
1
Expert's answer
2013-01-24T08:05:46-0500
Conservation of momentum (northis positive, south is negative velocities): 1590 kg * (-13.5 m/s) + 2540 kg * v = (1590 kg + 2540 kg) * 5.90 m/s; From this, v = ( (1590 kg + 2540 kg) * 5.90 m/s - 1590 kg * (-13.5 m/s) ) / (2540 kg) = 18.04 m/s
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
"assignmentexpert.com" is professional group of people in Math subjects! They did assignments in very high level of mathematical modelling in the best quality. Thanks a lot
Comments
Leave a comment