Answer to Question #227837 in Mechanics | Relativity for Smita

Question

A partical of mass m is hung by two light strings.the ends A and B are held by hands. The strings OA and OB make angle q with the vertical. Find the values of T and T' in terms of m and q

Answer 1

Gives

Angle=q

Daigram $\theta=q$

Lami theorem

$\frac{T}{sin(90+q)}=\frac{T}{sin(90+q)}=\frac{mg}{sin(180-2q)}$ Second and third part we can written as

$T=\frac{mg\times sin(90+q)}{sin(180-2q)}$

$T=\frac{mg\times cos(q)}{sin(2q)}$

$T=\frac{mg\times cos(q)}{2sin(q)cos(q)}$

$T=\frac{mg}{2sin (q)}$