Question #227837
A partical of mass m is hung by two light strings.the ends A and B are held by hands. The strings OA and OB make angle q with the vertical. Find the values of T and T' in terms of m and q
1
Expert's answer
2021-08-22T15:47:00-0400

Gives

Angle=q




Daigram θ=q\theta=q

Lami theorem

Tsin(90+q)=Tsin(90+q)=mgsin(1802q)\frac{T}{sin(90+q)}=\frac{T}{sin(90+q)}=\frac{mg}{sin(180-2q)} Second and third part we can written as

T=mg×sin(90+q)sin(1802q)T=\frac{mg\times sin(90+q)}{sin(180-2q)}

T=mg×cos(q)sin(2q)T=\frac{mg\times cos(q)}{sin(2q)}

T=mg×cos(q)2sin(q)cos(q)T=\frac{mg\times cos(q)}{2sin(q)cos(q)}

T=mg2sin(q)T=\frac{mg}{2sin (q)}

















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