Gives
Angle=q
Daigram θ=q\theta=qθ=q
Lami theorem
Tsin(90+q)=Tsin(90+q)=mgsin(180−2q)\frac{T}{sin(90+q)}=\frac{T}{sin(90+q)}=\frac{mg}{sin(180-2q)}sin(90+q)T=sin(90+q)T=sin(180−2q)mg Second and third part we can written as
T=mg×sin(90+q)sin(180−2q)T=\frac{mg\times sin(90+q)}{sin(180-2q)}T=sin(180−2q)mg×sin(90+q)
T=mg×cos(q)sin(2q)T=\frac{mg\times cos(q)}{sin(2q)}T=sin(2q)mg×cos(q)
T=mg×cos(q)2sin(q)cos(q)T=\frac{mg\times cos(q)}{2sin(q)cos(q)}T=2sin(q)cos(q)mg×cos(q)
T=mg2sin(q)T=\frac{mg}{2sin (q)}T=2sin(q)mg
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