Question #227688

A train of mass 4.0x10 kg runs south wards at a speed of 20m/s at a latitude 60 degree N what is the magnitude and direction of the coriolis force on tha train?


Expert's answer

Given:

m=4∗10 kgm=4*10\:\rm kg

v=20 m/sv=20\:\rm m/s

λ=60∘\lambda=60^{\circ}


The magnitude of the Coriolis force


Fc=2mvΩsin⁡λF_c=2mv\Omega\sin\lambda

Fc=2∗4∗10∗20∗2π24∗3600sin⁡60∘=0.1 NF_c=2*4*10*20*\frac{2\pi}{24*3600}\sin 60^{\circ}=0.1\:\rm N

The direction is northward.


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