Question

A point within 5 cm of electric current carrying wire has a large magnetic field of 10 Tesla. What is the magnetic field of a point within 16 cm of the electric current carrying wire ....

Answer 1

Question#22680

A point within 5 cm of electric current carrying wire has a large magnetic field of 10 Tesla. What is the magnetic field of a point within 16 cm of the electric current carrying wire ...

Answer:

According to the Biot-Savart law an equation that describes the magnetic field generated by electric current carrying wire is:

$$B = \frac {\mu}{4 \pi} \frac {2 I}{R}$$

Were $\mu$ is the magnetic constant, $I$ is the value of the current, $R$ is the distance from wire.

Such as magnitude of magnetic field linearly depends from distance, the magnitude in the current point is:

$$B = \frac {R _ {0}}{R} B _ {0}$$

Were $R_0$ is the distance to the previous point, $B_0$ is the magnitude in the previous point, $R$ is the distance of current point.

$$B = \frac {5}{16} 10 = 3.125 \text{ Tesla}$$

Answer: 3.125 Tesla.