25j of energy is stored in a capacitor ot capacitance 2NF . Determine the voltage across the capacitor terminal
"E=1\/2CV^2"
"2E=CV^2"
"V^2=2E\/C"
"V=\\sqrt{2E\/C}" ="\\sqrt{\\frac{(2\\times 25)}{2\\times 10^{-9}}}=158113.883" "V"
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