Question #225174
A 2.00 kg block is attached to a spring and force constant of the spring is k = 196 N/m.The block is
held a distance of 5.00 cm from equilibrium and released at t = 0.
(a) Find the angular frequency w, the frequency f, and the period T.
(b) Write an equation for x vs. time.
1
Expert's answer
2021-08-17T09:23:15-0400

Gives

K=196N/m

m=2.00kg

x=5.00cm

w2=kmw^2=\frac{k}{m}

Put value


w=1962=98=72rad/secw=\sqrt\frac{196}{2}=\sqrt{98}=7\sqrt2rad/sec


f=w2π=722πHzf=\frac{w}{2\pi}=\frac{7\sqrt2}{2\pi}Hz

T=2πw=2π72T=\frac{2\pi}{w}=\frac{2\pi}{7\sqrt2} Sec

Equation


F=kx(1)F=-kx\rightarrow(1)

F=md2xdt2=ma(2)F=m\frac{d^2x}{dt^2}=ma\rightarrow(2)

Equation (1) and )2) we can written as

d2xdt2=kmx\frac{d^2x}{dt^2}=-\frac{k}{m}x

d2xdt2+w2x=0\frac{d^2x}{dt^2}+w^2x=0


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