Answer to Question #223177 in Mechanics | Relativity for Kavi

Question

a s link having circular cross section is subjected to a load of 2KN shown in figure the diameter of the link is 30mm determine the maximum temsile strength and Maximum shear stress of the s link

Answer 1

Gives

F=2kN

Diameter (d)=30mm

Area=

$$A=\pi r^2\\A=3.14\times(0.015)^2=7.065\times 10^{-4}m^2$$

We know that

Maximum shear stress

$\sigma=\frac{F}{A}$

Put value

$$\sigma=\frac{2\times10^3}{7.065\times10^{-4}}=2.84\times10^6N/m^2$$