Question #223177

a s link having circular cross section is subjected to a load of 2KN shown in figure the diameter of the link is 30mm determine the maximum temsile strength and Maximum shear stress of the s link

Expert's answer

Gives

F=2kN

Diameter (d)=30mm

Area=

A=πr2A=3.14×(0.015)2=7.065×104m2A=\pi r^2\\A=3.14\times(0.015)^2=7.065\times 10^{-4}m^2

We know that

Maximum shear stress

σ=FA\sigma=\frac{F}{A}

Put value


σ=2×1037.065×104=2.84×106N/m2\sigma=\frac{2\times10^3}{7.065\times10^{-4}}=2.84\times10^6N/m^2










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