A large elevator uses a diesel engine with lift power P of 500kw to pull a cable lift which has a 1000 newton pull Fdrag when empty. The total vertical lift distance (d) is 400 meters. How many 60kg boxes can the elevator accommodate at one time if the vertical speed (v) of the elevator is 2m/s®?
1
Expert's answer
2013-01-21T07:36:45-0500
The power of engine is equal to P = F * d / t,t = d / V, where d = 400 m and V = 2 m/s. t = 400 / 2 = 200 s The maximum force that could be applied to a cable is: Fmax = P * t / d = 500000 * 200 / 400 = 250000 N The number of boxes can the elevator accommodate atone time is n = (Fmax - Fempty) / (m0 * g), where m0 is the mass of single box. n = (250000 - 1000) / (60 * 10) = 249000 / 600 = 2490 / 6 = 415 boxes.
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
Finding a professional expert in "partial differential equations" in the advanced level is difficult.
You can find this expert in "Assignmentexpert.com" with confidence.
Exceptional experts! I appreciate your help. God bless you!
Comments
Leave a comment