Question #2225
A 2000 kg car is traveling on a banked curved icy road without sliding. The velocity of the car is 30 m/s and the road is banked at an angle of 20 degrees. What is the radius of curvature of the road?
I really need to know HOW to do it... not just the answer
I really need to know HOW to do it... not just the answer
Expert's answer
The support reaction must be ballansed by the vector sum of the weight and the centrifugal acceleration:
<img src="/cgi-bin/mimetex.cgi?%5Ctan%7B20%5E%7B%5Ccirc%7D%7D%20=%20%5Cfrac%7Bmv%5E2%7D%7BR%5Ccdot%20mg%7D%20=%5Cfrac%7B30%5E2%7D%7BR%5Ccdot%2010%7D%20%5C%5C%20R%20=%20%5Cfrac%7B900%7D%7B10%20%5Ctan%7B20%5E%7B%5Ccirc%7D%7D%7D=%20247.27%20%5C%20m" title="\tan{20^{\circ}} = \frac{mv^2}{R\cdot mg} =\frac{30^2}{R\cdot 10} \\ R = \frac{900}{10 \tan{20^{\circ}}}= 247.27 \ m">
<img src="/cgi-bin/mimetex.cgi?%5Ctan%7B20%5E%7B%5Ccirc%7D%7D%20=%20%5Cfrac%7Bmv%5E2%7D%7BR%5Ccdot%20mg%7D%20=%5Cfrac%7B30%5E2%7D%7BR%5Ccdot%2010%7D%20%5C%5C%20R%20=%20%5Cfrac%7B900%7D%7B10%20%5Ctan%7B20%5E%7B%5Ccirc%7D%7D%7D=%20247.27%20%5C%20m" title="\tan{20^{\circ}} = \frac{mv^2}{R\cdot mg} =\frac{30^2}{R\cdot 10} \\ R = \frac{900}{10 \tan{20^{\circ}}}= 247.27 \ m">
Learn more about our help with Assignments: MechanicsRelativity
