During the hammer throw at a track meet, an 8.0 kg hammer is accidentally thrown straight up. If 784.0 J of work were done on the hammer to give it vertical velocity, how high will it rise?
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Expert's answer
2013-01-14T11:10:26-0500
The energy conservation law: T+U = const T - kinetic energy U - potential energy T = m*v^2/2 U = m*g*h After the throw: A = T A + 0 = U + 0 A = m*g*h h= A/(m*g) = 784/(8*9.8)= 10 m
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