A large chunk of ice with a mass of 15.0 kg falls from a roof 8.00 m above the ground.
(a) What is the kinetic energy of the ice as it reaches the ground?
(b) What is its speed as it reaches the ground?
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Expert's answer
2013-01-14T11:02:02-0500
The energy conservation law: U + T = const T - kinetic energy U - potential energy T = m*v^2/2 U = m*g*h a) T = m*g*h = 15*8*10 =1200 J b) v = Sqrt[2T/m]=Sqrt[2*1200/15] = 4*Sqrt[10] m/s = 12.6 m/s
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