Question

Jogger runs 1km north, 5km west, and then a further 2km to the south-west in a total time of 45 minutes.

(a) draw an accurate scale diagram to find the jogger's resultant displacement vector and find both magnitude and direction.

Answer 1

Gives

Distance (OA) =1km

Distance (AB)=5km

Distance (BC)=2km

Distance (CD)=∆x

∆x=OA+AB-DO-BD+CD

Tringle CDB

$sin\theta=\frac{CD}{CB}$

$sin45°=\frac{CD}{2}$

$CD=\sqrt2$

Put value

$∆x=1+5-5-1+\sqrt2$

$∆x=\sqrt2$