Question

a gun fires a bullet of mass 50 gms. the bullet moves with a velocity of 100m/sec strikes a wooden plank and comes to rest on 0.05 seconds. calculate the force exerted by the wooden plank on the bullet

Answer 1

Question#22024

a gun fires a bullet of mass 50 gms. the bullet moves with a velocity of 100m/sec strikes a wooden plank and comes to rest on 0.05 seconds. calculate the force exerted by the wooden plank on the bullet

Solution:

Let:

$$m _ {1} = 5 0 g = 0. 0 5 k g$$ $$v _ {1} = 1 0 0 m / s$$ $$t = 0. 0 5 c$$ $$F =?$$

According to the law of conservation momentum:

$$m _ {1} v _ {1} = m _ {2} v _ {2},$$

were $m_2$ is the mas of wooden plank, $v_2$ is the velocity of wooden plank after striking

Such as:

$$v = a t$$

According to the second Newton's law:

$$m _ {1} v _ {1} = m _ {2} \frac {F}{m _ {2}} t$$ $$F = \frac {m _ {1} v _ {1}}{t}$$ $$F = \frac {0 . 0 5 * 1 0 0}{0 . 0 5} = 1 0 0 N$$

Answer: 100 N