Question #22004

Hi,
I need help with a momentum question. Here it is: Your spacecraft is travelling forward with a momentum of 4940 kgm/s. The space station is 40 degrees to the right. The thrusters on the spacecraft exert a force of 1112 N perpendicular to the motion. How many seconds should you turn the thruster on to change your heading to reach the station? I'm comfused and any help would be appreciated. Thanks.

Expert's answer

Your spacecraft is travelling forward with a momentum of 4940kgms4940\frac{kg \cdot m}{s} . The space station is 4040{}^{\circ} to the right. The thrusters on the spacecraft exert a force of 1112N1112N perpendicular to the motion. How many seconds should you turn the thruster on to change your heading to reach the station?

Solution.

p1\overrightarrow{p_1} - an initially momentum of the spacecraft;

p2\overrightarrow{p_2} - a final momentum of the spacecraft;

Δp\overrightarrow{\Delta p} - changing of the momentum of the spacecraft.

From diagram:


Δpp1=tanα;\frac {\Delta p}{p _ {1}} = \tan \alpha ;Δp=p1tanα.\Delta p = p _ {1} \tan \alpha .


If a force FF is applied to a spacecraft for a time interval tt , the momentum of the spacecraft changes by an amount:


Δp=Ft;\Delta p = F t;t=FΔp;t = \frac {F}{\Delta p};t=Fp1tana.t = \frac{F}{p_1 \tan a}.t=11124940tan40=0.27(s).t = \frac{1112}{4940 \cdot \tan 40{}^\circ} = 0.27(s).


Answer: t=0.27st = 0.27s.


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