Answer to Question #219530 in Mechanics | Relativity for dave

Question

if E=1/2mv2 .where m=52.4+ or _0.2,v=25.6+ or_0.1 what is the percentage error in F

Answer 1

$E=\frac{1}{2}mv^2$

Error

$\frac{∆E}{E}=\frac{∆m}{m}+2\frac{∆v}{v}$

$\frac{∆E}{E}=\frac{0.2}{52.4}+2\times \frac{0.1}{25.6}$

$\frac{∆E}{E}$ =0.00381+0.00781=0.01162

$\frac{∆E}{E}=0.01162$

Percentage error

$$\frac{∆E}{E}\times100=0.01162\times100=1.162$$

$\frac{∆E}{E}$%=1.162%