When the vertical lifting of a body weighing 2 kg to a height of 10 m was performed work 240 J. Determine the acceleration of the body.
Work (w)=240J
Mass(m)=2kg
Height (s)=10m
Work=F×\times× s
F=wsF=\frac{w}{s}F=sw
F=24010=24NF=\frac{240}{10}=24NF=10240=24N
We know that
F=ma
a=Fm=242=12m/sec2a=\frac{F}{m}=\frac{24}{2}=12m/sec^2a=mF=224=12m/sec2
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