Question

A 224 kg crate is pushed horizontally with a force of 710 N. if the coefficient of friction is .25, calculate the acceleration of the crate.

Answer 1

Question#21900

A 224 kg crate is pushed horizontally with a force of 710 N. if the coefficient of friction is .25, calculate the acceleration of the crate.

Solution:

Let:

$$m = 224\,kg$$ $$F = 710\,N$$ $$k = 0.25$$

According to the second Newton's law:

$$a = \frac{F - F_f}{m}, \text{ were } F_f \text{ is a friction force}$$ $$F_f = kmg$$

Were: $g = 9.8 \, \text{m/s}^2$ is the acceleration due the gravity.

$$a = \frac{F - kmg}{m}$$ $$a = \frac{710 - 0.25 \times 224 \times 9.8}{224} = 0.72 \, \text{m/s}^2$$

Answer: $0.72 \, \text{m/s}^2$