Task:
What is the magnitude of momentum of a 22 g sparrow flying with a speed of 8.1 m/s?
Solution:
p=mvp = mvp=mv, where
ppp – momentum,
mmm – mass,
vvv – velocity
Given:
m=22 g=0.022 kg,m = 22\ g = 0.022\ kg,m=22 g=0.022 kg,
v=8.1 m/sv = 8.1\ m/sv=8.1 m/s
p=mv=0.022 kg⋅8.1 ms=0.1782 kg⋅msp = mv = 0.022\ kg \cdot 8.1\ \frac{m}{s} = 0.1782\ \frac{kg \cdot m}{s}p=mv=0.022 kg⋅8.1 sm=0.1782 skg⋅m
Answer:
p=0.1782 kg⋅msp = 0.1782\ \frac{kg \cdot m}{s}p=0.1782 skg⋅m
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