Answer to Question #218168 in Mechanics | Relativity for lalala

Question

The bulk modulus of water is 1.9GPa. Compute the volume contraction of 65 mL of water when subjected to a pressure of 3.3 MPa.

Answer 1

We know that

bulk modulus

$\beta=\frac{∆P}{\frac{∆V}{V}}\rightarrow(1)$

$∆P=3.3MPa\\V=65mL\\\beta=1.9GPa$

Put value formula

equation (1) put value

$1.9\times10^{9}=\frac{3.3\times10^6}{\frac{∆V}{65\times10^{-3}}}$

$1.9\times10^{9}=\frac{3.3\times10^6}{∆V}\times{{65\times10^{-3}}}$

$∆V=\frac{3.3\times10^6}{1.9\times10^{9}}\times{{65\times10^{-3}}}$

$∆V=1.128\times10^{-4}liter$