Question #21815

A 850N painter stands 1.2m from on end of a 3.0m scaffold supported at each end by a step ladder. The scaffold weighs 250N and there is a 40.0N paint can .50m from the end opposite the painter. How much force is exerted by each step ladder?

Expert's answer

Question

We will have next equations:

For the left end of the ladder:


Rright3=8501.2+2501.5+402.5=1020+375+100=1495(Nm)Rright=1495(Nm)3(m)=498.3(N).\begin{array}{l} R_{\text{right}} \cdot 3 = 850 \cdot 1.2 + 250 \cdot 1.5 + 40 \cdot 2.5 = 1020 + 375 + 100 = 1495(N \cdot m) \Rightarrow \\ \Rightarrow R_{\text{right}} = \frac{1495(N \cdot m)}{3(m)} = 498.3(N). \end{array}


And for the sum of the forces at equilibrium:


Rright+Rleft=850+250+40=1140(N)Rleft=1140(N)498.3(N)=641.7(N).R_{\text{right}} + R_{\text{left}} = 850 + 250 + 40 = 1140(N) \Rightarrow R_{\text{left}} = 1140(N) - 498.3(N) = 641.7(N).


Answer: 641.7(N).

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

LATEST TUTORIALS
APPROVED BY CLIENTS