Question
We will have next equations:
For the left end of the ladder:
Rright⋅3=850⋅1.2+250⋅1.5+40⋅2.5=1020+375+100=1495(N⋅m)⇒⇒Rright=3(m)1495(N⋅m)=498.3(N).
And for the sum of the forces at equilibrium:
Rright+Rleft=850+250+40=1140(N)⇒Rleft=1140(N)−498.3(N)=641.7(N).
Answer: 641.7(N).