A student wearing frictionless in-line skates in a horizontal surface is pushed by a friend with a constant force of 45N. How far must the student be pushed, starting from rest her final kinetic energy is 352J?
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Expert's answer
2013-01-08T11:43:42-0500
T=A=F*d T - the kinetic energy A - the work done by a constant force of magnitude F on a body that moves a distance d in the direction of the force is the product d=T/F=325/45=7.22 m
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